Chemistry - Gas Laws - Ideal gas law (PV=nRT) - PV=nRT Worked Examples

4 worked examples. Show R values: R = 0.0821 L·atm/(mol·K) or R = 8.314 J/(mol·K). Example 1: 'Find V of 2 mol gas at 1 atm, 273K.' PV=nRT → V=nRT/P = (2)(0.0821)(273)/(1) = 44.8 L. (Makes sense: 1 mol=22.4L at STP, so 2 mol=44.8L!) Example 2: 'Find P of 0.5 mol gas in 10L at 300K.' P=nRT/V = (0.5)(

Edodovivmagarwal
Chemistry - Gas Laws - Ideal gas law (PV=nRT) - PV=nRT Worked Examples
Log in

Preparing your experience...

Loading scripts and resources

Comments (0)

0/5000

Comments are reviewed before appearing publicly.

About this Experience

Chemistry - Gas Laws - Ideal gas law (PV=nRT) - PV=nRT Worked Examples

vivmagarwal
vivmagarwalJan 29, 2026

Description

4 worked examples. Show R values: R = 0.0821 L·atm/(mol·K) or R = 8.314 J/(mol·K). Example 1: 'Find V of 2 mol gas at 1 atm, 273K.' PV=nRT → V=nRT/P = (2)(0.0821)(273)/(1) = 44.8 L. (Makes sense: 1 mol=22.4L at STP, so 2 mol=44.8L!) Example 2: 'Find P of 0.5 mol gas in 10L at 300K.' P=nRT/V = (0.5)(

Details

ChemistryGas LawsClass 11, AS Level, Class 11, DP Grade 11, Grade 11

Engagement

15

Likes

0

Remixes

0

Comments

Browse all experiences