Chemistry - Gas Laws - Dalton's law of partial pressures - Dalton's Law Walkthrough
3 worked examples. Example 1: 'A container has 0.5 mol N₂ and 0.3 mol O₂ at 300K in 10L. Find partial pressures and total pressure.' Work: P_N₂ = n_N₂RT/V = (0.5)(0.0821)(300)/10 = 1.23 atm. P_O₂ = (0.3)(0.0821)(300)/10 = 0.74 atm. P_total = 1.23 + 0.74 = 1.97 atm. OR: n_total = 0.8 mol, P_total = (